Math, asked by bhavya4244, 3 months ago

PLS ANSWER FROM Q4 TO Q6.​

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Answers

Answered by madhurane78
1

Answer:

1)

2.5 cm, 6.5 cm, 6 cm

by pythagoras theorem

LHS = (2.5)² +6²

= 42.25

RHS = 6.52

= 42.25

Hence a right triangle is form as

LHS RHS

=

(ii) 2 cm, 2 cm, 5 cm

by pythagoras theorem

LHS = 2² +2²

= 8

=

RHS = 5² = 25

LHS RHS Hence No right

angle

(iii) 1.5

cm,

2

cm,

2.5 cm

by pythagoras theorem

LHS = 1.5² +2²= 6.25

RHS = 2.52 = 6.25

LHS = RHS Hence right angle triangle

Step-by-step explanation:

Let us consider, the larger side be

the hypotenuse and also using

Pythagoras theorem,

(Hypotenuse)² = (Base)² + (Perpendicular)²

AB = 2 cm, BC = 2 cm,

AC = 5 cm

In AABC,

(AC)² = (AB)² + (BC)²

⇒ (5)² = (2)² + (2)²

⇒ L.H.S=

:(5)² = 25

⇒ R.H.S

= (2)² + (2)² = 4 + 4 = 8

Since, L.H.S R.H.S.

Therefore, the given sides are not

of the right angled triangle.

3)

Let us consider, the larger side be the hypotenuse and also using Pythagoras theorem,

(Hypotenuse)2 = (Base)2 + (Perpendicular)²

1.5 cm, 2 cm, 2.5 cm

In APQR, (PR)² = (PQ)² + (RQ)² L.H.S. (25)2 = 6.25cm

R.H.S.

= (1.5)² + (2)² = 2.25 + 4 = 6.25

cm Since, L. H. S. = R. H.S.

Therefore, the given sides are of

the right angled triangle.

Right angle lies opposite to the greater side 2.5 cm

Answered by prachidhruw
4

Answer:

The diagram is for Q5.

hope this answer helps you dear...take care and plz just drop multiple thanks dear!.

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