PLS ANSWER FROM Q4 TO Q6.
Answers
Answer:
1)
2.5 cm, 6.5 cm, 6 cm
by pythagoras theorem
LHS = (2.5)² +6²
= 42.25
RHS = 6.52
= 42.25
Hence a right triangle is form as
LHS RHS
=
(ii) 2 cm, 2 cm, 5 cm
by pythagoras theorem
LHS = 2² +2²
= 8
=
RHS = 5² = 25
LHS RHS Hence No right
angle
(iii) 1.5
cm,
2
cm,
2.5 cm
by pythagoras theorem
LHS = 1.5² +2²= 6.25
RHS = 2.52 = 6.25
LHS = RHS Hence right angle triangle
Step-by-step explanation:
Let us consider, the larger side be
the hypotenuse and also using
Pythagoras theorem,
(Hypotenuse)² = (Base)² + (Perpendicular)²
AB = 2 cm, BC = 2 cm,
AC = 5 cm
In AABC,
(AC)² = (AB)² + (BC)²
⇒ (5)² = (2)² + (2)²
⇒ L.H.S=
:(5)² = 25
⇒ R.H.S
= (2)² + (2)² = 4 + 4 = 8
Since, L.H.S R.H.S.
Therefore, the given sides are not
of the right angled triangle.
3)
Let us consider, the larger side be the hypotenuse and also using Pythagoras theorem,
(Hypotenuse)2 = (Base)2 + (Perpendicular)²
1.5 cm, 2 cm, 2.5 cm
In APQR, (PR)² = (PQ)² + (RQ)² L.H.S. (25)2 = 6.25cm
R.H.S.
= (1.5)² + (2)² = 2.25 + 4 = 6.25
cm Since, L. H. S. = R. H.S.
Therefore, the given sides are of
the right angled triangle.
Right angle lies opposite to the greater side 2.5 cm
Answer:
The diagram is for Q5.
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step-by-step explanation:
