Math, asked by Anonymous, 7 months ago

pls answer.... I don't need unwanted answers..​

Attachments:

Answers

Answered by XDeepinderKaurX
2

Answer:

We have

Radius of the well =

2

7

m

Depth of the well =10 m

Volume of the earth dug =π(

2

7

)

2

×10m

3

=

7

22

×

2

7

×

2

7

×10m

3

=358m

3

Also we have

Length of the field=14m

breadth of the field =14m

Area of the field =20×14m

2

=280m

2

Area of the base of the well =π(

2

7

)

2

m

2

=

7

22

×

2

7

×

2

7

m

2

=

2

77

m

2

Area of the remaining part of the field = Area of the field - Area of the base of the field

=(280−

2

77

)m

2

=

2

483

m

3

Let the rise in the level of the field be h metres

Volume of the raised field = Area of the base × height =(

2

483

×h)m

3

But volume of the raised field = Volume of the earth dugout

2

483

×h=385⇒h=

483

2×385

=1.594m

Rise in the level of the field=1.594m

Similar questions