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Answer:
We have
Radius of the well =
2
7
m
Depth of the well =10 m
Volume of the earth dug =π(
2
7
)
2
×10m
3
=
7
22
×
2
7
×
2
7
×10m
3
=358m
3
Also we have
Length of the field=14m
breadth of the field =14m
Area of the field =20×14m
2
=280m
2
Area of the base of the well =π(
2
7
)
2
m
2
=
7
22
×
2
7
×
2
7
m
2
=
2
77
m
2
Area of the remaining part of the field = Area of the field - Area of the base of the field
=(280−
2
77
)m
2
=
2
483
m
3
Let the rise in the level of the field be h metres
Volume of the raised field = Area of the base × height =(
2
483
×h)m
3
But volume of the raised field = Volume of the earth dugout
2
483
×h=385⇒h=
483
2×385
=1.594m
Rise in the level of the field=1.594m
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