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Hey mate here is ur answer
sin theta=opposite/hypotenuse.
Given sin theta=3/5.
(hypotenuse)^2=(opposite)^2+(adjacent)^2
(5)^2=(3)^2+(x)^2
25=9+(x)^2
25-9=(x)^2
16=(x)^2
x=√16
x=4.
Therefore adjacent side =4.
Now asking cos theta and tan theta
cos theta=adjacent/hypotenuse
cos theta=4/5.
tan theta=opposite/adjacent
tan theta=3/4.
Therefore cos theta and tan theta are 4/5&3/4 respectively.
Hope it helps you ✌✌
pls mark it as a brainliest answer....
sin theta=opposite/hypotenuse.
Given sin theta=3/5.
(hypotenuse)^2=(opposite)^2+(adjacent)^2
(5)^2=(3)^2+(x)^2
25=9+(x)^2
25-9=(x)^2
16=(x)^2
x=√16
x=4.
Therefore adjacent side =4.
Now asking cos theta and tan theta
cos theta=adjacent/hypotenuse
cos theta=4/5.
tan theta=opposite/adjacent
tan theta=3/4.
Therefore cos theta and tan theta are 4/5&3/4 respectively.
Hope it helps you ✌✌
pls mark it as a brainliest answer....
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