Question

pls answer I will give 20 points and mark u as brainlist answer 17th question ​

Answer 1

Answer:

5/100×20000=1000/-

1000×6=6000/-

interest earned is RS 6000/-

Answer 2

Solution

now.. the compound interest is

$= > p(i) - p = p(1 + \frac{r}{100}) {}^{nt} - p = p((1 + \frac{r}{100} ) {}^{nt} - 1) \\ now.... \\ p = 20000 \\ r = 5 \\ t = 6years \\ n = 1(compounded \: anually \: so) \\ so \: the \: interest \: is \\ = 20000((1 + \frac{5}{100} ) {}^{1 \times 6} - 1) \\ = 20000(( \frac{21}{20} ) {}^{6} - 1) \\ = 20000(( (\frac{21}{20} ) {}^{3} ) {}^{2} - 1 {}^{2} ) \\ = 20000(( \frac{21}{20} ) {}^{3} - 1 ) (( \frac{21}{20}) {}^{3} + 1) \\ = 20000 \times ( \frac{21 {}^{3} - 20 {}^{3} }{20 {}^{3} } )( \frac{21 {}^{3} + 20 {}^{3} }{20 {}^{3} } ) \\ = 20000 \times \frac{1261}{8000} \times \frac{17261}{8000} \\ = 6801.91 \: rs$

the compound interest is =6801.91 Rs