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Answer:
Math.PI/6)*((Math.pow(z,4)-(2*Math.PI))
____
More about Math Functions:-
Math.ceil(a) - Rounds the number upto next higher integer. Return data type: Double
Math.floor(a) - Rounds the number upto next lower integer. Return data type: Double.
Math.max(a,b)- Returns the maximum value between two parameters. Return data type: Depends on the data type of the parameters.
Math.min(a,b)- Returns minimum value between two parameters. Return data type: Depends on the data type of the parameters.
Math.cbrt(a)- Returns cube root. Return data type: Double.
Math.sqrt(a)- Returns square root. Return data type: Double.
Math.log(a)- Returns natural logarithmic value of a given argument. Return data type: Double.
Math.round(a)- Returns the number rounded to the nearest integer. (For more info: Please check the Knowledge box given at last.)
Math.rint(a)- Returns the nearest integer of a given number. Return data type: double
Math.exp(a)- Returns exponential value of a given argument. Return data type: double
Math.random()- There are no argument in this function and it returns random number between 0 and 1. Return data type: double
Math.PI - Returns the value of pi(π)
_______
Knowledge Box...!
It is necessary to know that round() and rint() are not same.
Math.round() returns number in int data type while Math.rint() returns number in double data type.
Another Difference... Let's take -9.5 as a parameter Math.round(-9.5) will return -9 while Math.rint(-9.5) returns -
Answer:
z=cos
4
π
+isin
6
π
z=
2
1
+i
2
1
θ=tan
−1
2
1
2
1
=tan
−1
(
2
2
)
θ=tan
−1
(
2
1
)
∴argz=tan
−1
2
1
∣z∣=
(
2
1
)
2
+(
2
1
)
2
=
2
1
+
4
1
=
4
2+1
=
2
3
z=cos
4
π
+isin
4
pi
argz=angle=
4
π
and ∣z∣=cos
2
4
π
+sin
2
4
π
=1