Question

pls answer i will mark as brainliest​

Answer 1

$\large\rm{\underbrace{\red{CONCEPT:-}}}$

$\checkmark\:\rm{\boxed{\sin{(90\:-\:\theta)}\:=\:\cos\theta}}$

$\checkmark\:\rm{\boxed{\cos{(90\:-\:\theta)}\:=\:\sin\theta}}$

$\checkmark\:\rm{\boxed{\tan{(90\:-\:\theta)}\:=\:\cot\theta}}$

$\checkmark\:\rm{\boxed{\cot{(90\:-\:\theta)}\:=\:\tan\theta}}$

$\checkmark\:\rm{\boxed{\sec{(90\:-\:\theta)}\:=\:\cosec\theta}}$

$\checkmark\:\rm{\boxed{\cosec{(90\:-\:\theta)}\:=\:\sec\theta}}$

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$\sin( \theta) . \csc( \theta) = 1 \\ \\ \cos( \theta) . \sec( \theta) = 1 \\ \\ \tan( \theta). \cot( \theta) = 1$

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$\large\rm{\underbrace{\red{CALCULATION:-}}}$

$\frac{ \cos(90 - \theta ). \sec(90 - \theta ). \tan( \theta ) }{ \csc(90 - \theta ). \sin(90 - \theta ). \cot(90 - \theta ) } + \frac{ \tan(90 - \theta ) }{ \cot( \theta ) } \\ \\ = \frac{ \sin( \theta ). \csc( \theta ). \tan( \theta ) }{ \sec( \theta ). \cos( \theta ). \tan( \theta ) } + \frac{ \cot( \theta ) }{ \cot( \theta ) } \\ \\ = \frac{1}{1} + 1 \\ \\ = 1 + 1 \\ \\ = 2$