Pls answer
If 1+ sin² A =3 sinAcosA
Then prove tanA=1 or ½
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1 + sin²A = 3 sinA cos A
cos²A + 2 sin²A = 3 sinA cosA (1= cos²A + sin² A)
cotanA + 2 tanA = 3 ( all this * tan A)
1 + 2 tan²A =3 tanA
2 tan²A - 3 tanA +1 = 0
2 (tanA -1)*(tanA-1/2) =0
then tan A = 1 or tan A =1/2
:)))
cos²A + 2 sin²A = 3 sinA cosA (1= cos²A + sin² A)
cotanA + 2 tanA = 3 ( all this * tan A)
1 + 2 tan²A =3 tanA
2 tan²A - 3 tanA +1 = 0
2 (tanA -1)*(tanA-1/2) =0
then tan A = 1 or tan A =1/2
:)))
nandini2106:
can u make the last step bit clear
the brackets and colon sign doesn't mean anything
no the step in which u factorised it
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