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class 9 math 3 mark question
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x = 64 degree ( interior alternate angle)
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Answer:
∴∠DCE+∠CEF=180o [∵ Co-interior angles]
⇒xo+∠CEF=180o⇒∠CEF=(180−xo)
Again, EF || AB and AE is the transversal.
∠BAE+∠AEF=180 o[∵ Co-interior angles]
⇒105o+∠AEC+∠CEF=180o
⇒105o+25o+(180o−xo)=180o
⇒310−xo=180o
Hence, x=130o
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