Question

pls answer if u r a physics expert

Answer 1

Initial velocity(u) = 40m/s
Final velocity when stone reaches at max. height(v) = 0m/s
g( accln due to gravity)= 10m/s2
g is taken as -ve because it opposes the vertical motion
max. height of the stone reach (h) = ?
Using Equation
v2 = u2 +2as
v2 - u2 = 2gh
0- u2 = -2gh
h= u2 /2g
= (40)2 /2*10
h= 80 m
hence, max. height attained by the stone is 80 meter

Answer 2

for this I have used projectile component of max height=u²sin²°/2g
so it will 80 m