Math, asked by shagun279, 11 months ago

pls answer ill mark as brilliant​

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Answered by sarita3057
0

Step-by-step explanation:

value of x is 55as

angle c a b is equal to 80 degree as it forms linear pair

now let the ratios be

angle abc is equal to y and angle abd is equal to 3y

3y + y is equal to180 as it forms a straight line therefore y is equal to 45 degree then by angle sum property y +x+80=180 so the value of x is 55 degree

Answered by pranavithathineni
0

Answer:

here is your answer:

Step-by-step explanation:

let ∠DAB = 1y and ∠BAC = 3y           (given; ratio 1:3)

consider line DE,

∠DAB + ∠BAC +∠EAC = 180°             ( angles on a straight line)

⇒  y + 3y + 108° = 180°                        (∠EAC = 108° ; given)

⇒  4y = 180° - 108°

⇒  4y = 72°

       y = 72°/4

  ∴  y = 18°

⇒ ∠DAB = 18° and ∠BAC = 3×18°

                                          = 54°

consider ΔDAB,

As DB = AB, ΔDAB is isosceles ⇒ ∠DAB = ∠BDA = 18°

∴ ∠BDA + ∠DAB + ∠ABD = 180°         (Angle sum property of triangle)

⇒ 18° + 18° + ∠ABD = 180°

⇒∠ABD = 180° - 36°

∴ ∠ABD = 144°

∠ABD + ∠ABC = 180°          (linear pair)

⇒ 144° + ∠ABC = 180°

⇒ ∠ABC = 180° - 144°

∴ ∠ABC = 36°                      ( YOU CAN DO THIS USING EXTERIOR ANGLE

                                               PROPERTY ALSO)

consider Δ ABC,

∠BAC + ∠ACB + ∠ABC = 180°                 ( angle sum property of triangle)

54° + x + 36° = 180°

⇒ x + 90° = 180°

⇒ x = 180° - 90°

∴ x= 90°

∴ ∠ACB = x = 90°

hope this helps you!!!!

pls mark my ans as the brainliest one.

(spent a lot of time typing this answer)

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