Question

Pls answer immediately
To prove 1 / sin a + cos a + 1 / sin a - cos a = 2 sin a / 1 - 2 cos a ^ 2

Answer 1

Consider the LHS: (1-sinA+cosA)2 = [(1-sinA) + cosA]2 = (1-sinA)2 + cos2A + 2(1-sinA)cosA = 1 + sin2A − 2sinA + cos2A + 2(1-sinA)cosA = 1 + (sin2A + cos2A) − 2sinA + 2(1-sinA)cosA = 1 + 1 − 2sinA + 2(1-sinA)cosA [Since, sin2A + cos2A =1] = 2 − 2sinA + 2(1-sinA)cosA = 2(1 − sinA) + 2(1-sinA)cosA = 2(1 − sinA)(1 + cosA)

Answer 2

hope this helps..........