Question

Pls answer, Input list of numbers and swap elements at the even location with the elements at the odd location in python?

Answer 1

Answer:

length := size of nums

for i in range 0 to length, increase by 4, do

if i+2<length, then

exchange nums[i] and nums[i+2]

if i+3<length, then

exchange nums[i+1] and nums[i+3]

return nums

Let us see the following implementation to get better understanding −

Example

Live Demo

class Solution:

def solve(self, nums):

length = len(nums)

for i in range(0,length,4):

if(i+2<length):

nums[i], nums[i+2] = nums[i+2], nums[i]

if(i+3<length):

nums[i+1], nums[i+3] = nums[i+3], nums[i+1]

return nums

ob = Solution()

nums = [1,2,3,4,5,6,7,8,9]

print(ob.solve(nums))

Input

[1,2,3,4,5,6,7,8,9]

Output

[3, 4, 1, 2, 7, 8, 5, 6, 9]