Question

pls answer it ......​

Answer 1

Answer:

$\frac{7 + 3 \sqrt{5} }{3 + \sqrt{5} } - \frac{7 - 3 \sqrt{5} }{3 - \sqrt{5} } = a + \sqrt{5} b \\ = \frac{(7 + 3 \sqrt{5} )(3 - \sqrt{5} ) - (7 - 3 \sqrt{5} )(3 + \sqrt{5}) }{(3 + \sqrt{5})(3 - \sqrt{5} ) } = a + \sqrt{5} b\\ = \frac{21 - 7 \sqrt{5} + 9 \sqrt{5} - 15 - 21 - 7 \sqrt{5} + 9 \sqrt{5} + 15}{9 - 5 } = a + \sqrt{5}b \\ = \frac{0 + 4 \sqrt{5} }{4} = a + \sqrt{5} b \\ = \sqrt{5} = a + \sqrt{5} b \\ = 0 + \sqrt{5} = a + \sqrt{5} b \\ so \\ = a = 0 \\ = \sqrt{5} b = \sqrt{5} \\ b = 1 \\ ansssssssssssss$

Step-by-step explanation:

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