Math, asked by vanshg28, 7 months ago

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CHAPTER:- AREA OF PARALLELOGRAM AND TRIANGLES CLASS 9

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Answered by sanjana9122
0

Answer:

Consider △AOC and △AOC

∠EBC=∠BCA and ∠BEC=∠ECA as they are alternate angles

Hence, as two angles are equal the third angle is also equal.

∠AOC=∠BOE

So, △AOC and △AOC are similar by AAA

And also,

∠AOB=180

−∠AOC=∠COE

Now, consider △AOB and △EOC

sides AO is proportional to OE

sides CO is proportional to OB

and ∠AOB=∠COE

Hence, △AOB and △EOC are similar by SAS

So,

∠ABC=∠BCE and ∠BAE=∠AEC property of similar triangles

So, AB∣∣CE

Hence, ABEC is a parallelogram.

Hope this will help you.......

Answered by evilqueen29
1

Answer:

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