Question

pls answer it fast .....​

Answer 1

Answer:

Step-by-step explanation:

In Δ ADG,E is the mid point of AD and EF║DG

So, F is the mid point of AG

⇒AF=FG

Now in ΔBCF,D is the mid point of BC and DG║BF

So,G is the mid point of FC

⇒FG=GC                          -

Now we know that

AF=FG=GC

Now,

AF+FG+GC=AC

AF+AF+AF=AC                                   (as AF=FG=GC)

3AF=AC

AF=1/3AC

Hence proved