Question

pls answer it fast.it is very urgent.without using trognometrical tables

Answer 1

Answer:

Step-by-step explanation:

=Sin35Cos55+Cos35Sin55/Cosec^2 10-Tan^2 80

=Sin35Sin(90-55)+Cos35Cos(90-55)/ Sec^2(90-10)-Tan^80

=Sin^2 35+Cos^2 35 /Sec^2 80- Tan^2 80

=1/1

{Sin^2 A+Cos^2 A=1}

{Sec^2 A-Tan^2 A=1}

=1