pls answer it fastttttt
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Initial momentum of the bullet=0.5×100=50kgm/s
As bullet comes to rest so final momentum will be 0.
By using equations of motion,
V^2=u^2-2as(as retarding so negative)
a=(-250000m/s^2)
Resistive force will be=0.5×250000
=125000N
I hope it helps you.☺
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