Question

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I want step by step
find the value of sin^2(2π/3)+cos^(25π/6)-tan^2(3π/4)​

Answer 1

Step-by-step explanation:

sin^2(2π/3)+cos^2(25π/6)-tan^2(3π/4) = 2sin^2 60+25cos^2 30 - 3tan^2 45

This is because π/3 = 60

                          π/4 = 45

                          π/6 = 30 , in radians

So, sin^2(2π/3)+cos^2(25π/6)-tan^2(3π/4) = $2(\sqrt{3} /2)^{2} + 25(\sqrt{3}/2 )^{2} - 3(\sqrt{3} )^{2}$

                                                                     = 2(3/4)+25(3/4) - 3(3)

                                                                     = 3/2 + 75/4 - 9

                                                                     = 45/4

                                                                     = 11.25

So 11.25 is your answer.