Question

pls answer it ok????​

Answer 1

The way I understood it, the ball travelled up vertically to a height of 100m in 7 seconds. It then travelled down for a further 2 seconds before landing on the cliff.

In that case, the height of the cliff is 100m minus the distance travelled in 2 seconds under freefall.

Using our trusty equations of motion,

s=ut+0.5∗at2

t=2,u=0,a=9.8

Plugging those values in, we get a distance of 19.6m. So the ball travelled down 19.6m after reaching a maximum height of 100m.

Subtracting the two, we get the height of the cliff to be 80.4m approx 80m

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