Question

pls answer it's my holiday homework​

Answer 1

Answer:

this answer is pythagorean.

Answer 2

Step-by-step explanation:

a) given,

(5,8,17)

let a=5,b=8, and c= 17

By using Pythagoras Theorem,

$c ^{2} = {a}^{2} + {b}^{2} \\ {17}^{2} = {5}^{2} + {8}^{2} \\ 289 = 25 + 64 \\ 289 = 89 \: wrong(i.e.false) \\ therefore \: it \: is \: not \: a \: pythagorean \: triplet$

b) given,

(8,15,17)

let a=7,b=15, and c=17

By using Pythagoras Theorem,

${c}^{2} = {a}^{2} + {b}^{2} \\ {17}^{2} = {8}^{2} + {15}^{2} \\ 289 = 64 + 225 \\ 289 = 289 \: right(i.e. \: true) \\ therefore \: it \: is \: a \: pythagorean \: triplet$

Hope it helps u.