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If [a+1]²+[b+1]² = 0, then a³+b³=?
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We know that if a + b + c = 0 then,
a^3 + b^3 + c^3 = 3abc;
Comparing with the given equation, we can see that c = -1.
So a + b + (-1) = 0
ie. a + b = 1.
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