Question

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Answer 1

$\Large\mathtt\green{} \huge\underline\mathtt\red{Answer : }$

The velocity at t = 4s will depend on the change in velocity of the particle in the interval 0 to 4 s which is given by the area under a-t graph. Before calculating area let us find the acceleration at t = 4 s.

Change in velocity = Area between 0 to 4 s1

= x(4+ 8) × 4 = 24m/s 2

final velocity (v) - initial velocity (u) = 24 v = u + 24 = 3+ 24 = 27m/s

Answer 2

Answer:

The velocity at t = 4 s will depend on the change in velocity of the particle in the interval 0 to 4 s which is given by the area under a-t graph. Before calculating area let us find the acceleration at t = 4 s.

tanθ=8−a04=88 (by the graph)

⇒ a0=4m/s2

Change in velocity =Area between 0 to 4 s

=12×(4+8)×4=24m/s

⇒ final velocity (v)−initial velocity (u) = 24

⇒ v=u+24=3+24=27m/s