pls answer it's urgent I'll mark beainliest
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60°
Step-by-step explanation:
Given,
CD ║ AB
⇒ CD ║ AF ( shown in the given diagram ),
Let ∠x and ∠DCE are linear pairs,
⇒ ∠x + m∠DCE= 180°,
⇒ ∠x + 75° = 180° ( by the diagram ),
⇒ ∠x = 180° - 75° = 105°,
By the alternate interior angle theorem,
∠x ≅ ∠1,
⇒ m∠x = m∠1
⇒ m∠1 = 105°,
Now, by the vertically opposite angle theorem,
∠1 ≅ ∠BEO,
⇒ m∠BEO = 105°,
Now, m∠EBO = 15°,
∵ BEO is a triangle,
⇒ m∠EBO + m∠BEO + m∠BOE = 180°,
⇒ 15° + 105° + m∠BOE = 180°,
⇒ 120° + m∠BOE = 180°,
⇒ m∠BOE = 60°,
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