pls answer it....
Trigonometry
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here is the ans mark it as brainliest
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Firstly, on lhs side divide sinA in each term,
=> cota-1+coseca/cota+1-coseca
=>cota+coseca-(cosec^2a-cot^2a)/cota-coseca+1
=>cota+coseca-[(coseca-cota)(coseca+cota)]/cota-coseca+1
=>cota+coseca[1-coseca+cota]/cota+1-coseca
=>cota+coseca
=>cosa/sina+1/sina
=>1+cosa/sina=rhs.....
Hence, proved!!
jainaakanksha0761:
ohk
but u also mark my ans as brainliest
but how to mark ans as brainliest
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