Question

Pls answer. Its urgent...

Answer 1

Answer:

$\alpha + \beta = \frac{ - b}{a} = \frac{ - 4b}{a} \\ \alpha \beta = \frac{c}{a} \\ but \: \: \beta = 3 \alpha \\ \alpha + 3 \alpha = \frac{ - 4b}{a} \\ 4 \alpha = \frac{ - 4b}{a} \\ \alpha = \frac{ - b}{a} \\ \alpha (3 \alpha ) = \frac{c}{a} \\ 3 { \alpha }^{2} = \frac{c}{a} \\ but \: \: \alpha = \frac{ - b}{a} \\ 3 {( \frac{ - b}{a} })^{2} = \frac{c}{a} \\ \frac{3 {b}^{2} }{ {a}^{2} } = \frac{c}{a} \\ \frac{3 {b}^{2} \times a}{ {a}^{2} \times c} = 1 \\ \frac{3 {b}^{2} }{ ac } = 1$