Question

pls answer
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Answer 1

Answer:

3km

Step by step explanation:

Given a train starts from rest.

So,initial velocity is zero

Time of travel,=5min=300sec

Velocity attended by the the train,v=72km/hr

=72×1000m/3600s

=20m/s

(I) Using first equation of motion,

Acceleration,a=v-u/t=20-0/300=1/5m/s

(II) Using second equation of motion,

Distance travelled,s=ut+1/2at square

=0×300+1/2×1/5×(300) square

=3000m

=3km