Question

pls answer me correctly fast with full steps by factor theorem ​

Answer 1

Answer:

X - 1 = 0

\mathfrak\red{x\:=\:1}x=1

p(X) = x² - 2x + 1

p(1) = 1² - 2(1) + 1

p(1) = 1 - 2 + 1

p(1) = 2 - 2

p(1) = 0

Hence, X+1 is a \mathfrak\green{factor}factor of the polynomial.

Answer 2

Answer:

Yes

Step-by-step explanation:

• f(x)=x²+2x+1
• x+1

If x+1 is a factor So,

x+1=0

x= -1

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put the value of x in f(x)

$\large{\longrightarrow x^2+2x+1}$

$\large{\longrightarrow (-1)^2+2(-1)+1}$

$\large{\longrightarrow 1-2+1}$

$\large{\longrightarrow 2-2}$

$\large{\longrightarrow 0}$

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Yes x+1 is a factor of f(x)= x²+2x+1