pls answer me fast...........................
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78
let solve it by another easy method,......
let the terms first term be a and common difference be d
10/2(2a+(n-1)d)=175
2a+(10-1)d=35
2a+9d=35......1)
sum of first 20 terms=175+475
=650
20/2(2a+(20-1)d)=650
2a+19d=65........2)
subtracting 1 from 2)
we get
10d=30
d=3
put this in first
2a=35-27
2a=8
a=4
hence required AP is,4,7,10,13......
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