pls answer me fast......
Attachments:
Answers
Answered by
0
Answer:
☝️we're is the question.........
Answered by
0
Answer:
Vertices of the triangle are A(−3,0), B(1,−3), C(4,1).
Distance between two points =
(
x
2
−x
1
)
2
+(y
2
−y
1
)
2
AB=
(1+3)
2
+(−3−0)
2
=5
BC=
(4−1)
2
+(1+3)
2
=5
AC=
(4+3)
2
+(1−0)
2
=5
2
AB=BC
Therefore, ΔABC is an isosceles triangle.
(AB)
2
+(BC)
2
=5
2
+5
2
=50
and (AC)
2
=(5
2
)
2
=50
∴(AB)
2
+(BC)
2
=(AC)
2
So, the triangle satisfies the Pythagoras theorem and hence it is a right angled triangle.
Similar questions