pls answer me giveme correct answer
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Answered by
0
Answer:
Here, The value of CosA in the given question is 15/17.
Step-by-step explanation:
Here, As per our given question,
As Given figure is a right triangle,
So, By applying pythagoras theorem, we get,
=H^2=P^2+B^2
=B^2=H^2-P^2
=B^2=(17)^2-(8)^2
=B^2=289-64
=B^2=225
By doing square root on both sides, we get,
=B=15cm
Now, As asked in question,
=CosA=B/h
=CosA=15/17
So, The value of CosA in the given question =15/17.
Thank you.
Answered by
1
Answer:
FIRST FIND THE ADJACENT SIDE BY PYTHAGORAS THEOREM
WHICH WILL BE EQUAL TO
H²=B²+P²
17²=ADJACENT ²+8²
289-64=ADJACENT ²
ADJACENT SIDE=√225
ADJACENT SIDE=15cm
NOW COS A=ADJACENT SIDE/HYPOTENUSE
COS A=15/17
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