Math, asked by Alyabhatt, 1 year ago

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Answered by HarishAS
5
Hey friend, Harish here.

Here is your answer.

To Find:

The dimensions of the rectangle.

Solution:

Let : Length = l units.

        Breadth = b units.

And Area = l×b sq.units

1 case:(When length increased by 5 units and breadth decreased by 3 units)

Area = Length × Breadth 

⇒ (lb - 25) = (l+5)(b-3)

⇒ lb - 25 = lb - 3l + 5b - 15

⇒ 3l -  5b = 10  - (i)

2nd case:(When length increased by 2 units, breadth increased by 5 units)

Area = length × breadth

⇒ lb + 285 = (l+2)(b+5)

⇒ lb + 285 = lb + 5l + 2b + 10

⇒ 5l + 2b = 275. - (ii)

Now solving for two variables with two equations (i) & (ii);

From (i) we get:

l =  \frac{5b+10}{3}

Now substituting l value in (ii) we get:

5 \left (  \frac{5b+10}{3} \right ) + 2 b = 275.

⇒  25b + 50 + 6b = 825

⇒ 31b = 775

⇒ b = 25\ units.

And l =  \frac{5(25) +10}{3} =  \frac{135}{3} = 45 \ units

\boxed{\bold{Therefore \ l = 45\ units, b = 25\ units}}
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Hope my answer is helpful to you.

Alyabhatt: thanks bro
HarishAS: Welcome sis
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