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Hey friend, Harish here.
Here is your answer.
To Find:
The dimensions of the rectangle.
Solution:
Let : Length = l units.
Breadth = b units.
And Area = l×b sq.units
1 case:(When length increased by 5 units and breadth decreased by 3 units)
Area = Length × Breadth
⇒ (lb - 25) = (l+5)(b-3)
⇒ lb - 25 = lb - 3l + 5b - 15
⇒ 3l - 5b = 10 - (i)
2nd case:(When length increased by 2 units, breadth increased by 5 units)
Area = length × breadth
⇒ lb + 285 = (l+2)(b+5)
⇒ lb + 285 = lb + 5l + 2b + 10
⇒ 5l + 2b = 275. - (ii)
Now solving for two variables with two equations (i) & (ii);
From (i) we get:
Now substituting l value in (ii) we get:
⇒
⇒
⇒
And
_____________________________________________________
Hope my answer is helpful to you.
Here is your answer.
To Find:
The dimensions of the rectangle.
Solution:
Let : Length = l units.
Breadth = b units.
And Area = l×b sq.units
1 case:(When length increased by 5 units and breadth decreased by 3 units)
Area = Length × Breadth
⇒ (lb - 25) = (l+5)(b-3)
⇒ lb - 25 = lb - 3l + 5b - 15
⇒ 3l - 5b = 10 - (i)
2nd case:(When length increased by 2 units, breadth increased by 5 units)
Area = length × breadth
⇒ lb + 285 = (l+2)(b+5)
⇒ lb + 285 = lb + 5l + 2b + 10
⇒ 5l + 2b = 275. - (ii)
Now solving for two variables with two equations (i) & (ii);
From (i) we get:
Now substituting l value in (ii) we get:
⇒
⇒
⇒
And
_____________________________________________________
Hope my answer is helpful to you.
Alyabhatt:
thanks bro
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