Physics, asked by Anonymous, 28 days ago

pls answer Mitron IX ICSE​

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Answered by RabiUdgata
1

Answer:

given as explanation.

Explanation:

VELOCITY BETWEEN 0-2s =  \frac{S_2-S_1}{t_2-t_1} = \frac{25-10}{2-0} = 7.5m/s^{2} [-ve sign due to decreasing displacement.

VELOCITY BETWEEN 8-12s = \frac{S_2-S_1}{t_2-t_1} = \frac{25-20}{12-8} = 1.25m/s^{2}

AVG VELOCITY BETWEEN 5-12s = \frac{S_2-S_1}{t_2-t_1} = \frac{25-10}{12-5} = 2.1m/s^{2}

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