Math, asked by baljinderkaur5243, 6 months ago

pls answer my last question ​

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Answers

Answered by mrmafia91
2

Answer:

a- i

b- iv

c-v

d-iii

e- ii

please mark as brainlist

Answered by ZAYNN
4

Answer:

Fill in the Blanks :

\begin{aligned}\sf a)\:\bigg\lgroup\dfrac{-\:2}{3}\bigg\rgroup \times \bigg\lgroup\dfrac{-\:2}{3}\bigg\rgroup \times \bigg\lgroup\dfrac{-\:2}{3}\bigg\rgroup \times \bigg\lgroup\dfrac{-\:2}{3}\bigg\rgroup=\bigg[...\bigg]^4  \\ \\ \sf = \bigg[\dfrac{-\:2}{3} \bigg]^4\end{aligned}

\begin{aligned}\sf b)\:(-\:3)^3 \times (-\:3)^4=... \\\\ \sf = (-\:3)^{(3 + 4)} \\\\ \sf =(-\:3)^7 \\ \\ \sf =  -  \:2187\end{aligned}

\rule{200}{1}

Evaluate :

a ) Find the value of x :

:\implies\sf \bigg\lgroup\dfrac{-\:7}{5}\bigg\rgroup^{11} \div \bigg\lgroup\dfrac{-\:7}{5}\bigg\rgroup^3=\bigg\lgroup\dfrac{-\:7}{5}\bigg\rgroup^{2x+2}\\\\\\:\implies\sf \bigg\lgroup\dfrac{-\:7}{5}\bigg\rgroup^{11 - 3} = \bigg\lgroup\dfrac{-\:7}{5}\bigg\rgroup^{2x + 2}\\\\\\:\implies\sf 11 - 3 = 2x + 2\\\\\\:\implies\sf 8 - 2 = 2x\\\\\\:\implies\sf 6 = 2x\\\\\\:\implies\sf \dfrac{6}{2} = x\\\\\\:\implies\sf x = 3

b ) Find the value of a :

:\implies\sf \Bigg[\bigg\lgroup\dfrac{3}{13}\bigg\rgroup^8\Bigg]^3=\bigg\lgroup\dfrac{3}{13}\bigg\rgroup^{a+1}\\\\\\:\implies\sf \bigg\lgroup\dfrac{3}{13}\bigg\rgroup^{(8 \times 3)} = \bigg\lgroup\dfrac{3}{13}\bigg\rgroup^{a + 1}\\\\\\:\implies\sf 8 \times 3 = a + 1\\\\\\:\implies\sf 24 = a + 1\\\\\\:\implies\sf 24 - 1 = a\\\\\\:\implies\sf a = 23

\rule{200}{1}

Match the column :

\sf\quad Column\:'A'\qquad Column\:'B'\\\sf (a) \:x^m  \times x^n\qquad\quad(v) \:x^{m+n}\\ \sf(b) \:x^m \div x^n\qquad\quad(iv) \:x^{m-n}\:\:(m > n)\\ \sf(c) \:(x^m)^n\qquad\qquad(i) \:(x)^mn\\ \sf(d) \:x^n y^n\qquad\qquad(iii) \:(xy)^n\\ \sf(e) \:x^0\qquad\qquad\quad(ii)1

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