Question

Pls answer my question....

Answer 1

Answer:

Given:

A particle of charge 10 μC is brought from infinity to a point P such that

2 mJ of work is done .

To find:

Potential at point P

Concept:

Potential Difference is the work done to transport a charged particle from one point to another.

$\boxed{ \sf{ \red{potential \: diff. = \dfrac{work}{charge}}}}$

Calculation:

Potential at Infinity = 0 volts,

Let :

$potential \: at \: point \: P = P_{p} \\ potential \: at \: infinity \: = P_{ \infty}$

Putting all the values in the above equation :

$\boxed{P_{p} - P_{ \infty} = \dfrac{work}{charge}}$

$= > P_{p} - 0 = \dfrac{2 \times {10}^{ - 3} }{10 \times {10}^{ - 6} }$

$= > P_{p} = 200 \: volts$

So final answer is :

Potential at point P = 200 volts