Question

pls answer my question-
25 points...pls...as many as u can

Answer 1

Then, clearly,

Area of the path = Area of rectangle EFGH – Area of rectangle ABCD

From the figure, we have

EF = 90 + 5 + 5Then, clearly,

Area of the path = Area of rectangle EFGH – Area of rectangle ABCD

From the figure, we have

EF = 90 + 5 + 5Then, clearly,

Area of the path = Area of rectangle EFGH – Area of rectangle ABCD

From the figure, we have

EF = 90 + 5 + 5Then, clearly,

Area of the path = Area of rectangle EFGH – Area of rectangle ABCD

From the figure, we have

EF = 90 + 5 + 5Then, clearly,

Area of the path = Area of rectangle EFGH – Area of rectangle ABCD

From the figure, we have

EF = 90 + 5 + 5

Answer 2

Answer:

Nice question bro........

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