Question

Pls Answer my question ⁉️​

Answer 1

given cubic polynomial is x^3-6x^2+11x-6

if X=1 we get 1-6+11-6=0

so 1 is a root of given polynomial

so dividing the given equation with

x-1 we get

x-1)x^3-6x^2+11x-6(x^2-5x+6

x^3-x^2

___________

-5x^2+11x

-5x^2+5x

_____________

6x-6

6x-6

_______________

0

so x^3-6x^2+11x-6=(x-1)(x^2-5x+6)

solving x^2-5x+6=0 to find roots

x^2-5x+6=0

x2-2x-3x+6=0

x(x-2)-3(x-2)=0

(x-3)(x-2)=0

x=3 , x= 2

therefore the zeroes of the polymial are 1,2&3