pls answer my question ⁉️
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Answers
Answered by
0
Explanation:
Correct option is
A
11
6
A
Let the conductors are connected individually across a battery of voltage V.
Thus resistance of 1st conductor R
1
=
1
V
Similarly, resistances of other conductors R
2
=
2
V
and R
3
=
3
V
Now these are connected in series.
Thus equivalent resistance of circuit R
eq
=R
1
+R
2
+R
3
∴ R
eq
=
1
V
+
2
V
+
3
V
=
6
11V
Thus current drawn will be I=
R
eq
V
∴ I=
11V/6
V
=
11
6
A
Answered by
0
Explanation:
R1 has lowest resistance and R3 has highest
hope it helpss
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