pls answer my question......
Attachments:
Answers
Answered by
0
Since, x+a is a factor,
putting x = -a will give 0.
1st eq) a^2 + ap + q is 0
2nd eq) a^2 + al + m is 0
2nd eq - 1st eq
= a(l-p) + m -q is 0
so, a is (q-m)/(l-p)
putting x = -a will give 0.
1st eq) a^2 + ap + q is 0
2nd eq) a^2 + al + m is 0
2nd eq - 1st eq
= a(l-p) + m -q is 0
so, a is (q-m)/(l-p)
Answered by
4
Answer:
=> x + a is the factor.
=> Substituting x = -a will give 0.
=> a^2 + ap + q = 0 [ 1st Equation ].
=> a^2 + al + m = 0 [ 2nd Equation ].
=> Now, 2nd Equation - 1st Equation.
=> a ( l - p ) + m - q = 0.
=> a = ( q - m ) / ( l - p ).
Step-by-step explanation:
Keep Smiling...
Similar questions