pls answer my question.................
Attachments:
Answers
Answered by
1
AB=AE-EB
4=2-EB
EB=4-2
EB=2CM
RADIUS OF SECTOR =EB=2CM
AB=BC=CD=DA
THUS ABCD IS SQUARE
LENGTH OF SQUARE=4
AREA OF SQUARE= L×L
=4×4
=16CM
AREA OF MINOR SECTOR=π×r×r×θ /360
=3.14×2×2×90/360
= 3.14
Area of shaded region= Area of square - Area
of sector
=16 - 3.14
= 12.68
4=2-EB
EB=4-2
EB=2CM
RADIUS OF SECTOR =EB=2CM
AB=BC=CD=DA
THUS ABCD IS SQUARE
LENGTH OF SQUARE=4
AREA OF SQUARE= L×L
=4×4
=16CM
AREA OF MINOR SECTOR=π×r×r×θ /360
=3.14×2×2×90/360
= 3.14
Area of shaded region= Area of square - Area
of sector
=16 - 3.14
= 12.68
Similar questions