Question

pls answer my question​

Answer 1

The reaction that is taking place here is

S8 + 8 O2 --------> 8 SO2

Given mass of sulphur = 6.4 X 10^-2 Kg or 64 g.

Molar mass of sulphur = 32 X 8 = 256 g.

Therefore, no. of moles of sulphur = Given mass/Molar mass

                                                         = 64/256

                                                          = 0.25 moles.

Now, according to given equation,

no. of moles of Sulphur dioxide produced by 1 mole sulphur = 8 moles

Therefore, no. of moles of sulphur dioxide produced by 0.25 moles of sulphur = 8 X 0.25 = 2 moles.

Now, no. of molecules of sulphur dioxide present in 1 mole = 6.022 X 10^23

Hence, no. of molecules of sulphur dioxide present in its 2 moles

= 2 X 6.022 X 10^23

= 12.044 X 10^23.

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Hope this will help you.