Question

PLS ANSWER MY QUESTION. A CYCLIST DRIVING AT 36 KM/H STOPS HIS CYCLE IN 2 SECOND , BY THE APPLICATION OF BRAKES. CALCULATE RETARDATION AND DISTANCE COVERED DURING THE APPLICATION OF BRAKES

Answer 1

we know that
= acceleration = v - u / t
given -
v = 0   , u = 36 km/h or by converting into m/s = 36 x 5/18 = 10 m/s
Time = 2 seconds
retardation is also called acceleration.
retardation =  v - u / t
= 0 - 10 / 2

retardation = 5 m/s² and acceleration =   - 5 m/s²

distance = by second equation of motion = 
s = ut + 1/2 at²
= 10x2 + 1/2 [ -5] [ 4 ]
= 20 + 1/2 [ -20 ]
= 20 - 10
= 10 m/s²

Answer 2

ans: is in pic

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