pls answer my question; find the root x square-12x-27=0
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I think it is
x²-12x+27=0 not( -27)
x²-9x-3x+27=0
x(x-9)-3(x-9)=0
(x-3)(x-9)=0
x=3 or 9
x²-12x+27=0 not( -27)
x²-9x-3x+27=0
x(x-9)-3(x-9)=0
(x-3)(x-9)=0
x=3 or 9
gadhaveeknath40:
thanks
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