Question

pls answer my question. If i am satisfied i will mark you as brainliest​

Answer 1

Answer:

First of all we have to find out the sum of total interior angles.

We have the formula ,

         $(n-2)*180$  

where, n is the total number of sides.    

  for decagon, the total sides , n = 10

now , by putting value of n in the above formula we get,

          $= (10-2)*180\\\\= 1440$

Now, ATQ

   $=> (3x +10)+(2x+7)+(4x-3)+(5x-2)+(2x+15)+(3x+2)+(x+3)+(2x+5)+(3x-1)+(3x+4)=1440\\\\=> 28x + 40=1440\\\\=> 28x = 1400\\\\=> x = 50 \\\\Now , angles = 3(50)+10 = 160 (i)\\\\= 2(50)+7=107 (ii)\\\\= 4(50) - 3 = 197 (iii)\\\\= 5(50) - 2 = 148 (iv)\\\\= 2(50) + 15 = 115 (v)\\\\= 3(50) + 2 = 152 (vi)\\\\= 1(50) + 3 = 53 (vii)\\\\= 2(50) + 5 = 105 (viii)\\\\= 3(50) -1 = 149 (ix)\\\\= 3(50) + 4 = 154 (x)$

                                             Hope it helps

                                 please mark as brainliest