Question

pls answer my question
In the figure below ,ABCD is a trapezium with ab||CD. find x​

Answer 1

Answer:

80

Step-by-step explanation:

∠A + ∠∠D = 180

x - 20 + x + 40 = 180

2x + 20 = 180

2x = 160

x = 80°

Answer 2

Answer

$\longrightarrow \tt x = 80^\circ$

Given:

ABCD is a trapezium.

AB║CD

∠A = x - 20°

∠D = x + 40°

Solution:

AB║CD

∴ ∠A + ∠D = 180° [Co-interior Angles]

X - 20° + x + 40° = 180°

2x + 20 = 180

2x = 180 - 20

2x = 160

$\tt x = \dfrac{160}{2}$

x = 80°

Finding ∠A and ∠B

∠A = x - 20°

∠A = 80° - 20°

∠A = 60°

∠B = x + 40°

∠B = 80 + 40

∠B = 120°

Solution.

$\longrightarrow \sf x = 80^\circ$

$\longrightarrow \sf \angle A = 60^\circ$

$\longrightarrow \sf \angle B = 120^\circ$