Question

pls answer my question pls​

Answer 1

Step-by-step explanation:

$f(x) = {x}^{3} - 4 {x}^{2} + x + 6 \\ \\ f(2) = 8 - 16 + 2 + 6 \\ \\ = - 8 + 8 \\ \\ = 0. \\ \\ therefore \: \: (x - 2) \: is \: a \: factor \: of \: f(x). \\ \\ \\ f(3) = 27 - 36+ 3 + 6 \\ \\ = 0. \\ \\ \\ therefore \: \: (x - 3) \: is \: a \: factor \: of \: f(x). \\ \\ \\ f( - 1) = - 1 - 4 - 1 + 6 \\ \\ = 0. \\ \\ therefore \: \: (x + 1) \: is \: a \: factor \: of \: f(x).$