Question

pls.answer my question.
the ratio of the ages of suma thand beena are 4:3.The sum of their ages are 28 years. Find their present age.​

Answer 1

✯✯ QUESTION ✯✯

The ratio of the ages of suma thand beena are 4:3.The sum of their ages are 28 years. Find their present age.

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✰✰ ANSWER ✰✰

$\longmapsto\tt{Let\:age\:of\:Suma\:be=4x}$

$\longmapsto\tt{Let\:age\:of\:Beena\:be=3x}$

$\longmapsto\tt{Sum\:of\:their\:ages=28}$

➥A.T.Q : -

$\longmapsto\tt{4x+3x=28}$

$\longmapsto\tt{7x=28}$

$\longmapsto\tt{x=\cancel\dfrac{28}{7}}$

$\green\longmapsto\:\large\underline{\boxed{\bf\red{x}\orange{=}\pink{4}}}$

☛Value of x is 4..

➥Now ,

$\longmapsto\tt{Present\:Age\:of\:Suma=4(4)}$

$\longmapsto\tt\bold{16\:yrs}$

$\longmapsto\tt{Present\:Age\:of\:Beena=3(4)}$

$\longmapsto\tt\bold{12\:yrs}$

Answer 2

16,12

Step-by-step explanation:

let suma age=4x

let beena age=3x

ATQ= 4x+3x=28

7x=28

x=4

substitute 4 in 4x and 3x

4x means 4 into x=4x4=16

3x means 3 into x=3x4=12

Suma age=16 years

beena age=12 years