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Step-by-step explanation:
OA is the radius of circle & AB is the chord
Now draw a perpendicular line from the chord to the centre of circle
Let us say the point on the chord ’D’
Now we can see two triangles ΔOAD &ΔOBD
In these two triangles we see that OA = OB & OD is common, So by the properties of triangles AD = DB = 3 cm
Now applying pythagoras theorem in triangle OAD (because it is a right angle triangle)
AO
2
=AD
2
+OD
2
(3.5)
2
=3
2
+OD
2
OD
2
=12.25−9=3.25 cm
OD=1.80 cm
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