Question

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Answer 1

Answer:

Area of The Quadrilateral ABCD is 66 cm²

Step-by-step explanation:

We Have :-

AC = 22 cm

BM = 3 cm

DN = 3 cm

$bm \: \perp \: ac \\ \\ dn \: \perp \: ac$

To Find :-

Area of Quadrilateral ABCD

Formula Used :-

$area \: of \: triangle \: = \: \dfrac{1}{2} \times base \times height$

Solution :-

We can take two triangles from Quadrilateral ABCD

$\triangle \: abc \\ \\ \triangle \: adc$

Area Of Triangle ABC :-

$area \: = \: \dfrac{1}{2} \times base \times height \\ \\ area \: = \: \dfrac{1}{2} \times 22 \times 3 \\ \\ area \: = \: 11 \times 3 \\ \\ area \: = \: 33 \: {cm}^{2}$

Area Of Triangle ADC :-

$area \: = \: \dfrac{1}{2} \times base \times height \\ \\ area \: = \: \dfrac{1}{2} \times 22 \times 3 \\ \\ area \: = \: 33 \: {cm}^{2}$

Area Of Quadrilateral ABCD :-

Area of Triangle ABC + Area of Triangle ADC

33 cm² + 33 cm²

66 cm²

Area of The Quadrilateral ABCD is 66 cm²

Answer 2

Given,

• AC = 22cm
• BM = 3cm
• DN = 3cm

To Find,

• The Area Of Quadrilateral ABCD.

Solution,

Area of Quadrilateral ABCD

→ ∆ABC + ∆ADC

In ∆ABC,

AC is The Base Of ∆ABC

BM is the height of ∆ABC

Area of ∆ABC = ½ × b × h

→ ½ × 22cm × 3cm

→ ½ × 66cm²

→ 33cm²

In ∆ADC,

AC is The Base Of ∆ADC

DN is the height of ∆ADC

Area of ∆ADC = ½ × b × h

→ ½ × 22cm × 3cm

→ ½ × 66cm²

→ 33cm²

Required Answer,

Area of Quadrilateral ABCD

→ ∆ABC + ∆ADC

Area of Quadrilateral ABCD

→ 33cm² + 33cm²

→ 66cm²