Question

Pls answer on paper n send the pic...thanq

n no spams...​

Answer 1

Answer :

Now, $\displaystyle \mathsf{\int_{0}^{\frac{\pi}{4}} cos2x\:dx}$

= $\displaystyle \mathsf{[\frac{sin2x}{2}]_{0}^{\frac{\pi}{4}}}$

= $\displaystyle \mathsf{\frac{sin\frac{\pi}{2}}{2}-\frac{sin0}{2}}$

= 1 - 0

= 1

Rule :

$\displaystyle \mathsf{\int_{a}^{b} cosmx\:dx=[\frac{sinmx}{m}]_{a}^{b}}$

where a and b are limits.