Math, asked by Anonymous, 1 month ago

pls answer only if u know. ​

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Answered by TwilightShine
9

1) Write expressions for the following statements.

A) 5 added to y.

B) p multiplied by 7.

C) 10 subtracted from x.

D) p added to 9.

E) x divided by 12.

F) p multiplied by 7 and then 10 added to the product.

G) -y multiplied by 5.

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Answer :-

A) y + 5.

This is because y is a variable here, and when we add 5 to it, we get y + 5.

B) 7p.

This is because p is the variable here, and when we multiply it by 7, we get 7p.

C) x - 10.

This is because x is the variable here, and when we subtract 10 from it, we get x - 10. If we were asked to subtract x from 10, then the expression would be "10 - x."

D) 9 + p.

This is because p is the variable here, and when we add it to 9, we get 9 + p.

E)   \sf\dfrac{x}{12}

This is because x is the variable here, and when we divide it by 12, we get   \sf\dfrac{x}{12}

F) 7p + 10.

This is because p is the variable here, and when we multiply it by 7, we get 7p. This is the product, and then we are asked to add 10 to the product. So that means we have to add 10 to 7p, thus by adding 10 to 7p, we get the expression 7p + 10.

G) - 5y.

This is because - y is the variable here, and when we multiply it by 5, we get - 5y. It can also be written as - y5.

Answered by Anonymous
8

Question -:

  • A ) 5 added to y .

  • B ) p is multiplied by 7 .

  • C ) 10 Subtract from x .

  • D ) p added to 9.

  • E ) x devided by 12 .

  • F ) p multiplied by 7 and then 10 added to the product.

  • G ) -y multiplied by 5 .

AnswEr-:

  1. \red{\mathrm {\dag{ \underline {A ) \: y + 5 }}}}
  2. \red{\mathrm {\dag{ \underline {B ) \: p \times  7 \:or\:7p}}}}
  3. \red{\mathrm {\dag{ \underline {C ) \: x - 10  }}}}
  4. \red{\mathrm {\dag{ \underline {D ) \: p + 9  }}}}
  5. \red{\mathrm {\dag{ \underline {E ) \: \dfrac{x}{12}  }}}}
  6. \red{\mathrm {\dag{ \underline {F ) \: 7p + 10  }}}}
  7. \red{\mathrm {\dag{ \underline {G ) \: -y \times 5\:or\: -5y }}}}

Explanation-:

\mathrm {\dag{Solution \:of\:Question \:-:}}

_________________________________________________________

  • Answer of A -:

  • A ) 5 added to y .

  • Here , y is a variable and Given that variable (y ) is added to 5 .

  • Therefore,

  • \red{\mathrm {\dag{ \underline {A ) \: y + 5 }}}}

_________________________________________________________

  • Answer of B -:

  • B ) p is multiplied by 7 .

  • Here , p is a variable and Given that variable (p) is multiplied by 9

  • Therefore,

  • \red{\mathrm {\dag{ \underline {B ) \: p \times  7 \:or\:7p}}}}

_________________________________________________________

  • C ) Answer of C -:

  • C ) 10 Subtract from x .

  • Here , x is a variable and Given that 10 is subtracted from variable (x) .

  • Therefore,

  • \red{\mathrm {\dag{ \underline {C ) \: x - 10  }}}}

_________________________________________________________

  • Answer of D -:

  • D ) p added to 9.

  • Here , p is Variable and Given that variable (p) is added to 9 .

  • Therefore,

  • \red{\mathrm {\dag{ \underline {D ) \: p + 9  }}}}

_________________________________________________________

  • Answer of E -:

  • E ) x devided by 12 .

  • Here , x is variable and Given that variable (x) is devided by 12 .

  • Therefore,

  • \red{\mathrm {\dag{ \underline {E ) \: \dfrac{x}{12}  }}}}

_________________________________________________________

  • Answer of F -:

  • F ) p multiplied by 7 and then 10 added to the product.

  • Here , p is a variable and Given that variable (p) is multiplied by 7 and by multiplying 7 to p we get (7p) and the product (7p) is added to 10 .

  • Therefore,

  • \red{\mathrm {\dag{ \underline {F ) \: 7p + 10  }}}}

_________________________________________________________

  • Answer of G -:

  • G ) -y multiplied by 5 .

  • Here , -y is a variable and Given that variable (-y) is multiplied by 5 .

  • Therefore,

  • \red{\mathrm {\dag{ \underline {G ) \: -y \times  5\:or\:-5y  }}}}

_______________________________________________________

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